3(y+4)=(y-1)

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Solution for 3(y+4)=(y-1) equation: 



3(y+4)=(y-1)

We move all terms to the left:

3(y+4)-((y-1))=0

We multiply parentheses

3y-((y-1))+12=0



We calculate terms in parentheses: -((y-1)), so:

(y-1)

We get rid of parentheses

y-1

Back to the equation:

-(y-1)



We get rid of parentheses

3y-y+1+12=0

We add all the numbers together, and all the variables

2y+13=0

We move all terms containing y to the left, all other terms to the right

2y=-13

y=-13/2

y=-6+1/2

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