12(3v+1)-6=-(-6-6v)

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Solution for 12(3v+1)-6=-(-6-6v) equation: 



12(3v+1)-6=-(-6-6v)

We move all terms to the left:

12(3v+1)-6-(-(-6-6v))=0

We add all the numbers together, and all the variables

12(3v+1)-(-(-6v-6))-6=0

We multiply parentheses

36v-(-(-6v-6))+12-6=0



We calculate terms in parentheses: -(-(-6v-6)), so:

-(-6v-6)

We get rid of parentheses

6v+6

Back to the equation:

-(6v+6)



We add all the numbers together, and all the variables

36v-(6v+6)+6=0

We get rid of parentheses

36v-6v-6+6=0

We add all the numbers together, and all the variables

30v=0

v=0/30

v=0

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