12(3+c)=6(c+13)

Solution for 12(3+c)=6(c+13) equation:

12(3+c)=6(c+13)

We move all terms to the left:

12(3+c)-(6(c+13))=0

We add all the numbers together, and all the variables

12(c+3)-(6(c+13))=0

We multiply parentheses

12c-(6(c+13))+36=0


We calculate terms in parentheses: -(6(c+13)), so:

6(c+13)

We multiply parentheses

6c+78

Back to the equation:

-(6c+78)


We get rid of parentheses

12c-6c-78+36=0

We add all the numbers together, and all the variables

6c-42=0

We move all terms containing c to the left, all other terms to the right

6c=42

c=42/6

c=7