12(2z+1)=3(8z+4)

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Solution for 12(2z+1)=3(8z+4) equation: 



12(2z+1)=3(8z+4)

We move all terms to the left:

12(2z+1)-(3(8z+4))=0

We multiply parentheses

24z-(3(8z+4))+12=0



We calculate terms in parentheses: -(3(8z+4)), so:

3(8z+4)

We multiply parentheses

24z+12

Back to the equation:

-(24z+12)



We get rid of parentheses

24z-24z-12+12=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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