3(t+2)=(2+3t)+4

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Solution for 3(t+2)=(2+3t)+4 equation: 



3(t+2)=(2+3t)+4

We move all terms to the left:

3(t+2)-((2+3t)+4)=0

We add all the numbers together, and all the variables

3(t+2)-((3t+2)+4)=0

We multiply parentheses

3t-((3t+2)+4)+6=0



We calculate terms in parentheses: -((3t+2)+4), so:

(3t+2)+4

We get rid of parentheses

3t+2+4

We add all the numbers together, and all the variables

3t+6

Back to the equation:

-(3t+6)



We get rid of parentheses

3t-3t-6+6=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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