12(2x-3)=10(3x+2)

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Solution for 12(2x-3)=10(3x+2) equation: 



12(2x-3)=10(3x+2)

We move all terms to the left:

12(2x-3)-(10(3x+2))=0

We multiply parentheses

24x-(10(3x+2))-36=0



We calculate terms in parentheses: -(10(3x+2)), so:

10(3x+2)

We multiply parentheses

30x+20

Back to the equation:

-(30x+20)



We get rid of parentheses

24x-30x-20-36=0

We add all the numbers together, and all the variables

-6x-56=0

We move all terms containing x to the left, all other terms to the right

-6x=56

x=56/-6

x=-9+1/3

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