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15(x-1)=6(x+2)
We move all terms to the left:
15(x-1)-(6(x+2))=0
We multiply parentheses
15x-(6(x+2))-15=0
We calculate terms in parentheses: -(6(x+2)), so:We get rid of parentheses
6(x+2)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
15x-6x-12-15=0
We add all the numbers together, and all the variables
9x-27=0
We move all terms containing x to the left, all other terms to the right
9x=27
x=27/9
x=3
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