12(2)+2x=16(2)+(x-2)2

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Solution for 12(2)+2x=16(2)+(x-2)2 equation: 



12(2)+2x=16(2)+(x-2)2

We move all terms to the left:

12(2)+2x-(16(2)+(x-2)2)=0



We calculate terms in parentheses: -(162+(x-2)2), so:

162+(x-2)2

determiningTheFunctionDomain
(x-2)2+162

We multiply parentheses

2x-4+162

We add all the numbers together, and all the variables

2x+158

Back to the equation:

-(2x+158)



We get rid of parentheses

2x-2x-158+122=0

We add all the numbers together, and all the variables

-36!=0

There is no solution for this equation

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