.14x+.2(x-4)=0.01(4x-2)

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Solution for .14x+.2(x-4)=0.01(4x-2) equation:



.14x+.2(x-4)=0.01(4x-2)
We move all terms to the left:
.14x+.2(x-4)-(0.01(4x-2))=0
We multiply parentheses
.14x+0.2x-(0.01(4x-2))-0.8=0
We calculate terms in parentheses: -(0.01(4x-2)), so:
0.01(4x-2)
We multiply parentheses
0.04x-0.02
Back to the equation:
-(0.04x-0.02)
We add all the numbers together, and all the variables
0.34x-(0.04x-0.02)-0.8=0
We get rid of parentheses
0.34x-0.04x+0.02-0.8=0
We add all the numbers together, and all the variables
0.3x-0.78=0
We move all terms containing x to the left, all other terms to the right
0.3x=0.78
x=0.78/0.3
x=2+0.18/0.3

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