11y=10y(y+7)

Solution for 11y=10y(y+7) equation:

11y=10y(y+7)

We move all terms to the left:

11y-(10y(y+7))=0


We calculate terms in parentheses: -(10y(y+7)), so:

10y(y+7)

We multiply parentheses

10y^2+70y

Back to the equation:

-(10y^2+70y)


We get rid of parentheses

-10y^2+11y-70y=0

We add all the numbers together, and all the variables

-10y^2-59y=0

a = -10; b = -59; c = 0;
Δ = b2-4ac
Δ = -592-4·(-10)·0
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-59}{2*-10}=\frac{0}{-20}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+59}{2*-10}=\frac{118}{-20}
=-5+9/10
$