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3/5x-5/6x=13/15
We move all terms to the left:
3/5x-5/6x-(13/15)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
3/5x-5/6x-(+13/15)=0
We get rid of parentheses
3/5x-5/6x-13/15=0
We calculate fractions
(-2340x^2)/450x^2+270x/450x^2+(-375x)/450x^2=0
We multiply all the terms by the denominator
(-2340x^2)+270x+(-375x)=0
We get rid of parentheses
-2340x^2+270x-375x=0
We add all the numbers together, and all the variables
-2340x^2-105x=0
a = -2340; b = -105; c = 0;
Δ = b2-4ac
Δ = -1052-4·(-2340)·0
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11025}=105$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-105}{2*-2340}=\frac{0}{-4680} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+105}{2*-2340}=\frac{210}{-4680} =-7/156 $
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