11x2-7x-10=x2+9x-2

Solution for 11x2-7x-10=x2+9x-2 equation:

11x^2-7x-10=x2+9x-2

We move all terms to the left:

11x^2-7x-10-(x2+9x-2)=0

We add all the numbers together, and all the variables

11x^2-(+x^2+9x-2)-7x-10=0

We get rid of parentheses

11x^2-x^2-9x-7x+2-10=0

We add all the numbers together, and all the variables

10x^2-16x-8=0

a = 10; b = -16; c = -8;
Δ = b2-4ac
Δ = -162-4·10·(-8)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*10}=\frac{-8}{20}
=-2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*10}=\frac{40}{20}
=2
$