x+2=2(x-3)+3(x-4)

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Solution for x+2=2(x-3)+3(x-4) equation:



x+2=2(x-3)+3(x-4)
We move all terms to the left:
x+2-(2(x-3)+3(x-4))=0
We calculate terms in parentheses: -(2(x-3)+3(x-4)), so:
2(x-3)+3(x-4)
We multiply parentheses
2x+3x-6-12
We add all the numbers together, and all the variables
5x-18
Back to the equation:
-(5x-18)
We get rid of parentheses
x-5x+18+2=0
We add all the numbers together, and all the variables
-4x+20=0
We move all terms containing x to the left, all other terms to the right
-4x=-20
x=-20/-4
x=+5

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