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11x-4/x=10
We move all terms to the left:
11x-4/x-(10)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
11x*x-10*x-4=0
We add all the numbers together, and all the variables
-10x+11x*x-4=0
Wy multiply elements
11x^2-10x-4=0
a = 11; b = -10; c = -4;
Δ = b2-4ac
Δ = -102-4·11·(-4)
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{69}}{2*11}=\frac{10-2\sqrt{69}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{69}}{2*11}=\frac{10+2\sqrt{69}}{22} $
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