-6(x-2)+x=3x-20

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Solution for -6(x-2)+x=3x-20 equation: 



-6(x-2)+x=3x-20

We move all terms to the left:

-6(x-2)+x-(3x-20)=0

We add all the numbers together, and all the variables

x-6(x-2)-(3x-20)=0

We multiply parentheses

x-6x-(3x-20)+12=0

We get rid of parentheses

x-6x-3x+20+12=0

We add all the numbers together, and all the variables

-8x+32=0

We move all terms containing x to the left, all other terms to the right

-8x=-32

x=-32/-8

x=+4

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