11x-4(3-2x)=13x-5(x-3)

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Solution for 11x-4(3-2x)=13x-5(x-3) equation: 



11x-4(3-2x)=13x-5(x-3)

We move all terms to the left:

11x-4(3-2x)-(13x-5(x-3))=0

We add all the numbers together, and all the variables

11x-4(-2x+3)-(13x-5(x-3))=0

We multiply parentheses

11x+8x-(13x-5(x-3))-12=0



We calculate terms in parentheses: -(13x-5(x-3)), so:

13x-5(x-3)

We multiply parentheses

13x-5x+15

We add all the numbers together, and all the variables

8x+15

Back to the equation:

-(8x+15)



We add all the numbers together, and all the variables

19x-(8x+15)-12=0

We get rid of parentheses

19x-8x-15-12=0

We add all the numbers together, and all the variables

11x-27=0

We move all terms containing x to the left, all other terms to the right

11x=27

x=27/11

x=2+5/11

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