11x+4(-8)=9x+-2(6-8x)

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Solution for 11x+4(-8)=9x+-2(6-8x) equation: 



11x+4(-8)=9x+-2(6-8x)

We move all terms to the left:

11x+4(-8)-(9x+-2(6-8x))=0

We add all the numbers together, and all the variables

11x-(9x+-2(-8x+6))+4(-8)=0

We add all the numbers together, and all the variables

11x-(9x+-2(-8x+6))-32=0

We use the square of the difference formula

11x-(9x-2(-8x+6))-32=0



We calculate terms in parentheses: -(9x-2(-8x+6)), so:

9x-2(-8x+6)

We multiply parentheses

9x+16x-12

We add all the numbers together, and all the variables

25x-12

Back to the equation:

-(25x-12)



We get rid of parentheses

11x-25x+12-32=0

We add all the numbers together, and all the variables

-14x-20=0

We move all terms containing x to the left, all other terms to the right

-14x=20

x=20/-14

x=-1+3/7

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