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1/5x+3/4=1/2x
We move all terms to the left:
1/5x+3/4-(1/2x)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/5x-(+1/2x)+3/4=0
We get rid of parentheses
1/5x-1/2x+3/4=0
We calculate fractions
60x^2/160x^2+32x/160x^2+(-80x)/160x^2=0
We multiply all the terms by the denominator
60x^2+32x+(-80x)=0
We get rid of parentheses
60x^2+32x-80x=0
We add all the numbers together, and all the variables
60x^2-48x=0
a = 60; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·60·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*60}=\frac{0}{120} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*60}=\frac{96}{120} =4/5 $
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