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11=3/5(6x+19
We move all terms to the left:
11-(3/5(6x+19)=0
Domain of the equation: 5(6x+19)+11!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5(6x+19)!=-11
x∈R
-(3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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