2(4z+1+5z+2)=222

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Solution for 2(4z+1+5z+2)=222 equation: 



2(4z+1+5z+2)=222

We move all terms to the left:

2(4z+1+5z+2)-(222)=0

We add all the numbers together, and all the variables

2(9z+3)-222=0

We multiply parentheses

18z+6-222=0

We add all the numbers together, and all the variables

18z-216=0

We move all terms containing z to the left, all other terms to the right

18z=216

z=216/18

z=12

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