11=(z/3)+9

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Solution for 11=(z/3)+9 equation: 



11=(z/3)+9

We move all terms to the left:

11-((z/3)+9)=0

We add all the numbers together, and all the variables

-((+z/3)+9)+11=0

We multiply all the terms by the denominator


-((+z+11*3)+9)=0



We calculate terms in parentheses: -((+z+11*3)+9), so:

(+z+11*3)+9

We add all the numbers together, and all the variables

(z+33)+9

We get rid of parentheses

z+33+9

We add all the numbers together, and all the variables

z+42

Back to the equation:

-(z+42)



We get rid of parentheses

-z-42=0

We add all the numbers together, and all the variables

-1z-42=0

We move all terms containing z to the left, all other terms to the right

-z=42

z=42/-1

z=-42

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