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4(x+1)=-5(3x-2)+7x
We move all terms to the left:
4(x+1)-(-5(3x-2)+7x)=0
We multiply parentheses
4x-(-5(3x-2)+7x)+4=0
We calculate terms in parentheses: -(-5(3x-2)+7x), so:We get rid of parentheses
-5(3x-2)+7x
We add all the numbers together, and all the variables
7x-5(3x-2)
We multiply parentheses
7x-15x+10
We add all the numbers together, and all the variables
-8x+10
Back to the equation:
-(-8x+10)
4x+8x-10+4=0
We add all the numbers together, and all the variables
12x-6=0
We move all terms containing x to the left, all other terms to the right
12x=6
x=6/12
x=1/2
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