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114=(2x-3)(x)
We move all terms to the left:
114-((2x-3)(x))=0
We calculate terms in parentheses: -((2x-3)x), so:We get rid of parentheses
(2x-3)x
We multiply parentheses
2x^2-3x
Back to the equation:
-(2x^2-3x)
-2x^2+3x+114=0
a = -2; b = 3; c = +114;
Δ = b2-4ac
Δ = 32-4·(-2)·114
Δ = 921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{921}}{2*-2}=\frac{-3-\sqrt{921}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{921}}{2*-2}=\frac{-3+\sqrt{921}}{-4} $
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