114(m+3)=3(2m-2)

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Solution for 114(m+3)=3(2m-2) equation: 



114(m+3)=3(2m-2)

We move all terms to the left:

114(m+3)-(3(2m-2))=0

We multiply parentheses

114m-(3(2m-2))+342=0



We calculate terms in parentheses: -(3(2m-2)), so:

3(2m-2)

We multiply parentheses

6m-6

Back to the equation:

-(6m-6)



We get rid of parentheses

114m-6m+6+342=0

We add all the numbers together, and all the variables

108m+348=0

We move all terms containing m to the left, all other terms to the right

108m=-348

m=-348/108

m=-3+2/9

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