1120=(14+2x)(26+2x)

Solution for 1120=(14+2x)(26+2x) equation:

1120=(14+2x)(26+2x)

We move all terms to the left:

1120-((14+2x)(26+2x))=0

We add all the numbers together, and all the variables

-((2x+14)(2x+26))+1120=0

We multiply parentheses ..

-((+4x^2+52x+28x+364))+1120=0


We calculate terms in parentheses: -((+4x^2+52x+28x+364)), so:

(+4x^2+52x+28x+364)

We get rid of parentheses

4x^2+52x+28x+364

We add all the numbers together, and all the variables

4x^2+80x+364

Back to the equation:

-(4x^2+80x+364)


We get rid of parentheses

-4x^2-80x-364+1120=0

We add all the numbers together, and all the variables

-4x^2-80x+756=0

a = -4; b = -80; c = +756;
Δ = b2-4ac
Δ = -802-4·(-4)·756
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-136}{2*-4}=\frac{-56}{-8}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+136}{2*-4}=\frac{216}{-8}
=-27
$