110=(19x+4)+(8x-2)

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Solution for 110=(19x+4)+(8x-2) equation: 



110=(19x+4)+(8x-2)

We move all terms to the left:

110-((19x+4)+(8x-2))=0



We calculate terms in parentheses: -((19x+4)+(8x-2)), so:

(19x+4)+(8x-2)

We get rid of parentheses

19x+8x+4-2

We add all the numbers together, and all the variables

27x+2

Back to the equation:

-(27x+2)



We get rid of parentheses

-27x-2+110=0

We add all the numbers together, and all the variables

-27x+108=0

We move all terms containing x to the left, all other terms to the right

-27x=-108

x=-108/-27

x=+4

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