(5x2+20x+100)=0

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Solution for (5x2+20x+100)=0 equation:



(5x^2+20x+100)=0
We get rid of parentheses
5x^2+20x+100=0
a = 5; b = 20; c = +100;
Δ = b2-4ac
Δ = 202-4·5·100
Δ = -1600
Delta is less than zero, so there is no solution for the equation

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