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11/18+1/6a=1/3a
We move all terms to the left:
11/18+1/6a-(1/3a)=0
Domain of the equation: 6a!=0
a!=0/6
a!=0
a∈R
Domain of the equation: 3a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
1/6a-(+1/3a)+11/18=0
We get rid of parentheses
1/6a-1/3a+11/18=0
We calculate fractions
594a^2/324a^2+54a/324a^2+(-108a)/324a^2=0
We multiply all the terms by the denominator
594a^2+54a+(-108a)=0
We get rid of parentheses
594a^2+54a-108a=0
We add all the numbers together, and all the variables
594a^2-54a=0
a = 594; b = -54; c = 0;
Δ = b2-4ac
Δ = -542-4·594·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-54}{2*594}=\frac{0}{1188} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+54}{2*594}=\frac{108}{1188} =1/11 $
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