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10=1/5(5k+15)
We move all terms to the left:
10-(1/5(5k+15))=0
Domain of the equation: 5(5k+15))!=0We multiply all the terms by the denominator
k∈R
-(1+10*5(5k+15))=0
We calculate terms in parentheses: -(1+10*5(5k+15)), so:We add all the numbers together, and all the variables
1+10*5(5k+15)
determiningTheFunctionDomain 10*5(5k+15)+1
Wy multiply elements
50k(5+1
Back to the equation:
-(50k(5+1)
-(50k6=0
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