11/12z-7=40

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Solution for 11/12z-7=40 equation: 



11/12z-7=40

We move all terms to the left:

11/12z-7-(40)=0



Domain of the equation: 12z!=0

z!=0/12

z!=0

z∈R



We add all the numbers together, and all the variables

11/12z-47=0

We multiply all the terms by the denominator


-47*12z+11=0

Wy multiply elements

-564z+11=0

We move all terms containing z to the left, all other terms to the right

-564z=-11

z=-11/-564

z=11/564

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