40=7-11/12z

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Solution for 40=7-11/12z equation: 



40=7-11/12z

We move all terms to the left:

40-(7-11/12z)=0



Domain of the equation: 12z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

-(-11/12z+7)+40=0

We get rid of parentheses

11/12z-7+40=0

We multiply all the terms by the denominator


-7*12z+40*12z+11=0

Wy multiply elements

-84z+480z+11=0

We add all the numbers together, and all the variables

396z+11=0

We move all terms containing z to the left, all other terms to the right

396z=-11

z=-11/396

z=-1/36

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