11-2x-(3x+15)+22=-14+4(2x+5)-2(3x-12)-16+7x

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Solution for 11-2x-(3x+15)+22=-14+4(2x+5)-2(3x-12)-16+7x equation: 



11-2x-(3x+15)+22=-14+4(2x+5)-2(3x-12)-16+7x

We move all terms to the left:

11-2x-(3x+15)+22-(-14+4(2x+5)-2(3x-12)-16+7x)=0

We add all the numbers together, and all the variables

-2x-(3x+15)-(-14+4(2x+5)-2(3x-12)-16+7x)+33=0

We get rid of parentheses

-2x-3x-(-14+4(2x+5)-2(3x-12)-16+7x)-15+33=0



We calculate terms in parentheses: -(-14+4(2x+5)-2(3x-12)-16+7x), so:

-14+4(2x+5)-2(3x-12)-16+7x

determiningTheFunctionDomain
4(2x+5)-2(3x-12)+7x-14-16

We add all the numbers together, and all the variables

7x+4(2x+5)-2(3x-12)-30

We multiply parentheses

7x+8x-6x+20+24-30

We add all the numbers together, and all the variables

9x+14

Back to the equation:

-(9x+14)



We add all the numbers together, and all the variables

-5x-(9x+14)+18=0

We get rid of parentheses

-5x-9x-14+18=0

We add all the numbers together, and all the variables

-14x+4=0

We move all terms containing x to the left, all other terms to the right

-14x=-4

x=-4/-14

x=2/7

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