3b+12=3(b-5)

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Solution for 3b+12=3(b-5) equation: 



3b+12=3(b-5)

We move all terms to the left:

3b+12-(3(b-5))=0



We calculate terms in parentheses: -(3(b-5)), so:

3(b-5)

We multiply parentheses

3b-15

Back to the equation:

-(3b-15)



We get rid of parentheses

3b-3b+15+12=0

We add all the numbers together, and all the variables

27!=0

There is no solution for this equation

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