11-2(t-3)=5(2t+1)-6(t+3)

Solution for 11-2(t-3)=5(2t+1)-6(t+3) equation:

11-2(t-3)=5(2t+1)-6(t+3)

We move all terms to the left:

11-2(t-3)-(5(2t+1)-6(t+3))=0

We multiply parentheses

-2t-(5(2t+1)-6(t+3))+6+11=0


We calculate terms in parentheses: -(5(2t+1)-6(t+3)), so:

5(2t+1)-6(t+3)

We multiply parentheses

10t-6t+5-18

We add all the numbers together, and all the variables

4t-13

Back to the equation:

-(4t-13)


We add all the numbers together, and all the variables

-2t-(4t-13)+17=0

We get rid of parentheses

-2t-4t+13+17=0

We add all the numbers together, and all the variables

-6t+30=0

We move all terms containing t to the left, all other terms to the right

-6t=-30

t=-30/-6

t=+5