-2(2z+1)=26,z=

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Solution for -2(2z+1)=26,z= equation: 



-2(2z+1)=26.z=

We move all terms to the left:

-2(2z+1)-(26.z)=0

We add all the numbers together, and all the variables

-2(2z+1)-(+26.z)=0

We multiply parentheses

-4z-(+26.z)-2=0

We get rid of parentheses

-4z-26.z-2=0

We add all the numbers together, and all the variables

-30z-2=0

We move all terms containing z to the left, all other terms to the right

-30z=2

z=2/-30

z=-1/15

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