11(y+10)=(4y-5)

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Solution for 11(y+10)=(4y-5) equation: 



11(y+10)=(4y-5)

We move all terms to the left:

11(y+10)-((4y-5))=0

We multiply parentheses

11y-((4y-5))+110=0



We calculate terms in parentheses: -((4y-5)), so:

(4y-5)

We get rid of parentheses

4y-5

Back to the equation:

-(4y-5)



We get rid of parentheses

11y-4y+5+110=0

We add all the numbers together, and all the variables

7y+115=0

We move all terms containing y to the left, all other terms to the right

7y=-115

y=-115/7

y=-16+3/7

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