1(1+4m)=2(3+10m)

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Solution for 1(1+4m)=2(3+10m) equation: 



1(1+4m)=2(3+10m)

We move all terms to the left:

1(1+4m)-(2(3+10m))=0

We add all the numbers together, and all the variables

1(4m+1)-(2(10m+3))=0



We calculate terms in parentheses: -(2(10m+3)), so:

2(10m+3)

We multiply parentheses

20m+6

Back to the equation:

-(20m+6)



We get rid of parentheses

1(4m+1)-20m-6=0

We add all the numbers together, and all the variables

-20m+1(4m+1)-6=0

We move all terms containing m to the left, all other terms to the right

-20m+1(4m+1)=6

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