11(x-2)-2(4-3x)-4(1-2x)=17(x-1)+7

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Solution for 11(x-2)-2(4-3x)-4(1-2x)=17(x-1)+7 equation: 



11(x-2)-2(4-3x)-4(1-2x)=17(x-1)+7

We move all terms to the left:

11(x-2)-2(4-3x)-4(1-2x)-(17(x-1)+7)=0

We add all the numbers together, and all the variables

11(x-2)-2(-3x+4)-4(-2x+1)-(17(x-1)+7)=0

We multiply parentheses

11x+6x+8x-(17(x-1)+7)-22-8-4=0



We calculate terms in parentheses: -(17(x-1)+7), so:

17(x-1)+7

We multiply parentheses

17x-17+7

We add all the numbers together, and all the variables

17x-10

Back to the equation:

-(17x-10)



We add all the numbers together, and all the variables

25x-(17x-10)-34=0

We get rid of parentheses

25x-17x+10-34=0

We add all the numbers together, and all the variables

8x-24=0

We move all terms containing x to the left, all other terms to the right

8x=24

x=24/8

x=3

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