1(-9z-1)+4=-3(3z+4)+6

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Solution for 1(-9z-1)+4=-3(3z+4)+6 equation: 



1(-9z-1)+4=-3(3z+4)+6

We move all terms to the left:

1(-9z-1)+4-(-3(3z+4)+6)=0



We calculate terms in parentheses: -(-3(3z+4)+6), so:

-3(3z+4)+6

We multiply parentheses

-9z-12+6

We add all the numbers together, and all the variables

-9z-6

Back to the equation:

-(-9z-6)



We get rid of parentheses

1(-9z-1)+9z+6+4=0

We add all the numbers together, and all the variables

9z+1(-9z-1)+10=0

We move all terms containing z to the left, all other terms to the right

9z+1(-9z-1)=-10

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