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11(q-1)+5=3(q+1)-1
We move all terms to the left:
11(q-1)+5-(3(q+1)-1)=0
We multiply parentheses
11q-(3(q+1)-1)-11+5=0
We calculate terms in parentheses: -(3(q+1)-1), so:We add all the numbers together, and all the variables
3(q+1)-1
We multiply parentheses
3q+3-1
We add all the numbers together, and all the variables
3q+2
Back to the equation:
-(3q+2)
11q-(3q+2)-6=0
We get rid of parentheses
11q-3q-2-6=0
We add all the numbers together, and all the variables
8q-8=0
We move all terms containing q to the left, all other terms to the right
8q=8
q=8/8
q=1
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