1/5+(3m-6)+m=2

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Solution for 1/5+(3m-6)+m=2 equation: 



1/5+(3m-6)+m=2

We move all terms to the left:

1/5+(3m-6)+m-(2)=0

determiningTheFunctionDomain
(3m-6)+m-2+1/5=0

We add all the numbers together, and all the variables

m+(3m-6)-2+1/5=0

We get rid of parentheses

m+3m-6-2+1/5=0

We multiply all the terms by the denominator


m*5+3m*5+1-6*5-2*5=0

We add all the numbers together, and all the variables

m*5+3m*5-39=0

Wy multiply elements

5m+15m-39=0

We add all the numbers together, and all the variables

20m-39=0

We move all terms containing m to the left, all other terms to the right

20m=39

m=39/20

m=1+19/20

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