3(d-3)=4(2d+1)

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Solution for 3(d-3)=4(2d+1) equation: 



3(d-3)=4(2d+1)

We move all terms to the left:

3(d-3)-(4(2d+1))=0

We multiply parentheses

3d-(4(2d+1))-9=0



We calculate terms in parentheses: -(4(2d+1)), so:

4(2d+1)

We multiply parentheses

8d+4

Back to the equation:

-(8d+4)



We get rid of parentheses

3d-8d-4-9=0

We add all the numbers together, and all the variables

-5d-13=0

We move all terms containing d to the left, all other terms to the right

-5d=13

d=13/-5

d=-2+3/5

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