11(k-1)=7(k+3)

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Solution for 11(k-1)=7(k+3) equation: 



11(k-1)=7(k+3)

We move all terms to the left:

11(k-1)-(7(k+3))=0

We multiply parentheses

11k-(7(k+3))-11=0



We calculate terms in parentheses: -(7(k+3)), so:

7(k+3)

We multiply parentheses

7k+21

Back to the equation:

-(7k+21)



We get rid of parentheses

11k-7k-21-11=0

We add all the numbers together, and all the variables

4k-32=0

We move all terms containing k to the left, all other terms to the right

4k=32

k=32/4

k=8

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