11(2x-3)-4(3x-2)=4(-2x+1)+7

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Solution for 11(2x-3)-4(3x-2)=4(-2x+1)+7 equation: 



11(2x-3)-4(3x-2)=4(-2x+1)+7

We move all terms to the left:

11(2x-3)-4(3x-2)-(4(-2x+1)+7)=0

We multiply parentheses

22x-12x-(4(-2x+1)+7)-33+8=0



We calculate terms in parentheses: -(4(-2x+1)+7), so:

4(-2x+1)+7

We multiply parentheses

-8x+4+7

We add all the numbers together, and all the variables

-8x+11

Back to the equation:

-(-8x+11)



We add all the numbers together, and all the variables

10x-(-8x+11)-25=0

We get rid of parentheses

10x+8x-11-25=0

We add all the numbers together, and all the variables

18x-36=0

We move all terms containing x to the left, all other terms to the right

18x=36

x=36/18

x=2

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