2(x+5)=28-3(6+x)

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Solution for 2(x+5)=28-3(6+x) equation: 



2(x+5)=28-3(6+x)

We move all terms to the left:

2(x+5)-(28-3(6+x))=0

We add all the numbers together, and all the variables

2(x+5)-(28-3(x+6))=0

We multiply parentheses

2x-(28-3(x+6))+10=0



We calculate terms in parentheses: -(28-3(x+6)), so:

28-3(x+6)

determiningTheFunctionDomain
-3(x+6)+28

We multiply parentheses

-3x-18+28

We add all the numbers together, and all the variables

-3x+10

Back to the equation:

-(-3x+10)



We get rid of parentheses

2x+3x-10+10=0

We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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