10y-7(y+8)+13=13-6(2y+1)

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Solution for 10y-7(y+8)+13=13-6(2y+1) equation: 



10y-7(y+8)+13=13-6(2y+1)

We move all terms to the left:

10y-7(y+8)+13-(13-6(2y+1))=0

We multiply parentheses

10y-7y-(13-6(2y+1))-56+13=0



We calculate terms in parentheses: -(13-6(2y+1)), so:

13-6(2y+1)

determiningTheFunctionDomain
-6(2y+1)+13

We multiply parentheses

-12y-6+13

We add all the numbers together, and all the variables

-12y+7

Back to the equation:

-(-12y+7)



We add all the numbers together, and all the variables

3y-(-12y+7)-43=0

We get rid of parentheses

3y+12y-7-43=0

We add all the numbers together, and all the variables

15y-50=0

We move all terms containing y to the left, all other terms to the right

15y=50

y=50/15

y=3+1/3

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