5r-3=(1-r)/3

Solution for 5r-3=(1-r)/3 equation:

5r-3=(1-r)/3

We move all terms to the left:

5r-3-((1-r)/3)=0

We add all the numbers together, and all the variables

5r-((-1r+1)/3)-3=0

We multiply all the terms by the denominator


5r*3)-((-1r+1)-3*3)=0

We add all the numbers together, and all the variables

5r*3)-((-1r+1)=0

Wy multiply elements

15r^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$r=\frac{-b}{2a}=\frac{0}{30}=0$