10y-3(2y-7)=y+5

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Solution for 10y-3(2y-7)=y+5 equation: 



10y-3(2y-7)=y+5

We move all terms to the left:

10y-3(2y-7)-(y+5)=0

We multiply parentheses

10y-6y-(y+5)+21=0

We get rid of parentheses

10y-6y-y-5+21=0

We add all the numbers together, and all the variables

3y+16=0

We move all terms containing y to the left, all other terms to the right

3y=-16

y=-16/3

y=-5+1/3

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