(3x-10x)x=-8

Solution for (3x-10x)x=-8 equation:

(3x-10x)x=-8

We move all terms to the left:

(3x-10x)x-(-8)=0

We add all the numbers together, and all the variables

(-7x)x-(-8)=0

We add all the numbers together, and all the variables

(-7x)x+8=0

We multiply parentheses

-7x^2+8=0

a = -7; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-7)·8
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{14}}{2*-7}=\frac{0-4\sqrt{14}}{-14}
=-\frac{4\sqrt{14}}{-14}
=-\frac{2\sqrt{14}}{-7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{14}}{2*-7}=\frac{0+4\sqrt{14}}{-14}
=\frac{4\sqrt{14}}{-14}
=\frac{2\sqrt{14}}{-7}
$