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x+4x*2x=180
We move all terms to the left:
x+4x*2x-(180)=0
Wy multiply elements
8x^2+x-180=0
a = 8; b = 1; c = -180;
Δ = b2-4ac
Δ = 12-4·8·(-180)
Δ = 5761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{5761}}{2*8}=\frac{-1-\sqrt{5761}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{5761}}{2*8}=\frac{-1+\sqrt{5761}}{16} $
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